Use Python set intersection (&) to find common elements of two lists in O(n+m), returning them sorted. Learn set operators with live test cases.
The problem
Return the values found in both a and b, as a sorted list without duplicates. Use set operations.
Examples
Example 1
Input
common_sorted([1, 2, 3, 4], [3, 4, 5, 6])
Expected output
[3, 4]
Example 2
Input
common_sorted([9, 1, 9], [1, 9])
Expected output
[1, 9]
+ 2 hidden tests on Submit.
Edge cases to ask about
- No overlap
- Duplicates
- Empty list
Hints
0/3How an interviewer scores this
0/9Your code runs in real CPython inside your browser — nothing is sent anywhere. The first run downloads the interpreter (about 6 MB, once). Your code is saved on this device as you type.
Complexity Lab
What does this cost as n grows?
Interviewers score the analysis as much as the code. Commit to an answer first — then check it, and measure your code against the optimal one at growing input sizes.
Pick both to reveal the answer.
Measure it
Runs the function on inputs of size 250 up to 16,000 and records the time and peak memory. Slow solutions stop early — a short curve is itself the answer.
From brute force to optimal
The progression an interviewer wants to hear, one step at a time.
| Approach | Time | Space | Idea |
|---|---|---|---|
| Nested scans | O(n × m) | O(1) | |
| bestSet intersection | O(n + m + k log k) | O(n + m) | & is O(min(n, m)); sorting the k results adds k log k. |
Walkthrough of the optimal approach (try it yourself first)
set(a) & set(b) (or set(a).intersection(b)) gives the common values; sorted() makes the order deterministic. Know the four operators: | union, & intersection, - difference, ^ symmetric difference.
Complexity: O(n + m) time, O(n + m) space. Building both sets is linear and & is O(min(n, m)); sorting only the k common values adds k log k.
Reveal the reference solution
def common_sorted(a, b): return sorted(set(a) & set(b))
Follow-ups interviewers ask
- Keep the order of a instead of sorting (question 8).
Frequently asked interview questions
Core interview concepts, complexities, and follow-ups scored by hiring teams.
What is the time complexity of Common Elements Using Sets in Python?
The optimal solution runs in O(n + m) time and O(n + m) auxiliary space. Building both sets is linear and & is O(min(n, m)); sorting only the k common values adds k log k.
What is the brute-force approach, and how do you optimise it?
Nested scans: O(n × m) time, O(1) space. Set intersection: O(n + m + k log k) time, O(n + m) space. & is O(min(n, m)); sorting the k results adds k log k.
What follow-up questions do interviewers ask about Common Elements Using Sets?
Keep the order of a instead of sorting (question 8).
